【千年服务端】千年加密解密代码(delphi)
千年加密解密代码(delphi) 千年加密解密代码....虽然看起来挺复杂的.我是对应汇编的.编译后几乎和游戏客户端里的一样...保证了速度..二次解密代码我还没去搞.不过一次解密足够了.可以制出很多功能外挂.如自动拾取.吃药.等等...二次解密加密主要用于怪物坐标用的.(自动练功需要解析怪物坐标要用)
声明部分
//二种声方法均可
//const gamestr:string = ’N>TSVUJlwdcBMFjnAKb?qxvyeGzfLP=_ER@Z\am]ChgoWD;QuX[<tkpr^`iIHOYs.3‑"(- ’+chr(13)+’<; ’+chr(12)+chr(00)+’=/!,1>#2$’+chr(39)+’89%’+chr(10)+chr(9)+’*):
5&+67?40’;
const gamestr : array of byte =
($4E, $3E, $54, $53, $56, $55, $4A, $6C, $77, $64, $63, $42, $4D, $46, $6A,$6E, $41, $4B, $62, $3F, $71, $78, $76, $79, $65, $47, $7A, $66,$4C, $50, $3D, $5F,$45, $52, $40, $5A, $5C, $61, $6D, $5D, $43,$68, $67, $6F, $57, $44, $3B, $51, $75, $58, $5B, $3C, $74, $6B,$70, $72, $5E, $60, $69, $49, $48, $4F, $59, $73, $2E, $33, $1E,$01, $13, $22, $10, {&content}B, $28, $2D, $20, {&content}D, $19, $3C,$3B, $06, $11, $1C, {&content}C, {&content}, $3D, $1D, $2F,$21, $03, $02, $05, $04, $2C, $31, $3E, $23, $32, $24, $27, $38,$1F, $39, $25, $12, {&content}A, $09, $18, $1B, $2A, $29, $3A,{&content}E, $35, $07, $26, {&content}F, $2B, $36, $14, $37, $3F, $34,$30, $16, $08, $15, $17, $1A);
代码部分
function decode (inchar:pchar; len:integer ; outchar:pchar):integer; //解密
var
a1, d1: byte;
j, count, di, si :integer;
begin
decode := len div 4 * 3 ;//返回解密后数据长度
j := 0;
while i < len do
begin
d1 := byte (inchar );
if ( d1 = $3B ) or (d1 = $7A) then
begin
end;
d1 := d1 and {&content}FF;
d1 := gamestr ; //d1 := byte ( gamestr [ 1 + d1 ] );
byte (inchar ) := d1; // 根据不同的gamestr数据定义选用不现的方法
inc (i);
end;
di := 0 ;
si := 0 ;
count := len div 4 ; //循环次数
for j := 1 to count do
begin
a1 := ord ( inchar ); //解密数据 (取4个.转化3个)
a1 := a1 shl 2 ;
d1 := ord ( inchar );
d1 := d1 shr 4 ;
a1 := a1 or d1 ;
outchar := chr (a1);
a1 := ord ( inchar );
a1 := a1 shl 4 ;
d1 := ord ( inchar );
d1 := d1 shr 2 ;
a1 := a1 or d1 ;
outchar := chr (a1);
a1 := ord ( inchar );
a1 := a1 shl 6 ;
d1 := ord ( inchar );
a1 := a1 or d1 ;
outchar := chr (a1);
di := di + 4 ;
si := si + 3 ;
end;
end;function encode (inchar:pchar; len:integer ; outchar:pchar):integer; //加密
var
a1, d1 :byte;
j,count,di,si :integer;
begin
encode := len div 3 * 4 ;//返回加密后数据长度
di := 0 ;
si := 0 ;
count := len div 3; //定义循环次数
for j := 1 to count do
begin
a1 := ord ( inchar ); //第一次转换取3个 输出4个
a1 := a1 shr 2 ;
outchar := chr (a1);
a1 := ord (inchar);
a1 := a1 and 3 ;
a1 := a1 shl 4 ;
d1 := ord (inchar);
d1 := d1 shr 4 ;
a1 := a1 or d1 ;
outchar := chr (a1) ;
a1 := ord ( inchar) ;
a1 := a1 and {&content}F ;
a1 := a1 shl 2 ;
d1 := ord ( inchar) ;
d1 := d1 shr 6 ;
a1 := a1 or d1 ;
outchar := chr (a1);
a1 := ord ( inchar) ;
a1 := a1 and $3F;
outchar := chr (a1) ;
//第二次转换
d1 := ord ( outchar ); //第 1 个
d1 := gamestr ;
outchar := chr (d1);
d1 := ord ( outchar ); //第 2 个
d1 := gamestr ;
outchar := chr (d1);
d1 := ord ( outchar ); //第 3 个
d1 := gamestr ;
outchar := chr (d1);
d1 := ord ( outchar ); //第 4 个
d1 := gamestr ;
outchar := chr (d1);
di := di + 3 ;
si := si + 4 ;
end;
end;
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